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as we know
A + B + C = 180^°
A+ C= 180- B
A+ C /2= 180/2 -B/2
adding sin on both sides
sin (A+ C/2)= sin (90-B/2)
sin (A+C÷2=cos (B/2)
A + B + C = 180^°
A+ C= 180- B
A+ C /2= 180/2 -B/2
adding sin on both sides
sin (A+ C/2)= sin (90-B/2)
sin (A+C÷2=cos (B/2)
prathekkk:
thanks mam
Answered by
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Solution below......
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