Chemistry, asked by shipra8214, 9 months ago

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Answered by vineshrajkumar17
1

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Explanation:

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Answered by Eutuxia
2

Answer: The volume of the balloon is V=  4/ 3 πr³.

The radius of balloon is 10 m.

Hence, the volume of the balloon is V=4 / 3  ×3.1416×(10) ³  =4186.7m  ³.

The mass of displaced air is obtained from the product of volume and density. It is 4186.7 × 1.2=5024.04kg.

The number of moles of gas present are n=  PV/RT  =  1.666×4186.7×10³

                                                                                            0.083×300

                                                                                         =   279.11×10³.

Note: Here, the unit of volume is changed from m³ to dm³ .

      1m³ =1000dm³.

Mass of helium present is obtained by multiplying the number of moles with molar mass. It is 279.11×10³×4=1116.44×10  ³ g=1116.4 kg.

The mass of filled balloon is the sum of the mass of the empty balloon and the mass of He. It is  100+1116.4=1216.4 kg.

Pay load = mass of displaced air − mass of balloon

​=5024.04−1216.44=3807.6 kg

=5024.04−1216.44=3807.6 kg

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