Question

helpe to solve my question plsssss
square root of i​

Answer 1

hii friend......

√i =(i²)¹⁾⁴

          =(-1)^1/4

   or

√i=a+ib -----------------------(1)

i=(a+ib)²

i=a²+i²b²+2iab

i=a²-b²+2iab

comparing on both sides

a²-b²=0  and   2ab=1

a=b        and     a=1/2b

⇒1/2b=b

1/2=b²

b=±1/√2

a=±1/√2

substitute in (1)

√i=   ±[1/√2+i1/√2]

hope this helps you

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Answer 2

Answer:

where is the question...........?