helpe to solve my question plsssss
square root of i
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hii friend......
√i =(i²)¹⁾⁴
=(-1)^1/4
or
√i=a+ib -----------------------(1)
i=(a+ib)²
i=a²+i²b²+2iab
i=a²-b²+2iab
comparing on both sides
a²-b²=0 and 2ab=1
a=b and a=1/2b
⇒1/2b=b
1/2=b²
b=±1/√2
a=±1/√2
substitute in (1)
√i= ±[1/√2+i1/√2]
hope this helps you
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0
Answer:
where is the question...........?
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