Question

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Answer 1

Answer:

2 one jqjjahsjsshushsheheywu

Answer 2

Answer:

1. So, all the corresponding sides and angles of one triangle are equal to that of the other. And AB = CD. Therefore, it is proved that the diagonal of a parallelogram divides it into two congruent triangles and also opposite sides of a parallelogram are equal

2. Since opposite sides are equal in length, the squares on both diagonals are the same. We have already proven that a quadrilateral whose diagonals bisect each other is a parallelogram. Because ABCD is a parallelogram, its opposite sides are equal. (matching angles of congruent triangles).

3. Here we have AC=AC (common sides), ∠1=∠4 (alternate interior angles), and ∠2=∠3 (alternate interior angles). Thus, the two triangles are congruent, which means that ∠B=∠D. Similarly, we can show that ∠A=∠C. This proves that opposite angles in any parallelogram are equal.