Question

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Answer 1

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★ The sum of two numbers is 64 , and second number is 16 less than the first . Find the numbers.

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➙ The first number is 40 & second number is 24.

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Given :-

The sum of two numbers is 64 .

The second number is 16 less than the first.

To Find :-

The two number being added .

Solution :-

Let first number be ' x '

So , The Second number is x - 16

According to the question , The sum of two numbers is 64 .

x + ( x - 16 ) = 64

➝ x + x = 64 + 16

➝ x + x = 80

➝ 2 x = 80

➝ x = $\cancel{\dfrac{80}{2}}$

➝ x = 40

The first number is 40 .

The Second number is x - 16 =

➝ 40 - 16 = 24

So, The Second number is 24 .

$\mathtt{\huge{\bf{\underline{\pink{Let's\:Verify :-}}}}}$

The sum of two numbers is 64

➝ x + x - 16 = 64

➝ 40 + 24 = 64

➝64 = 64

➠ Hence, Verified .

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Answer 2

Step-by-step explanation:

Let one number be x and other y

x+y=64

y=x-16

putting value of y in eq. 1

x+x-16=64

2x=80

x=40

y=40-16=24

hope it is helpful to u