Math, asked by Kayeeee, 9 months ago

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sin³ A-8 /sinA-2 =sin²A+2sinA+4

Answers

Answered by sandy1816

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Step-by-step explanation:

sin³A-8/sinA-2

=sin³A-2³/sinA-2

=(sinA-2)(sin²A+2sinA+4)/(sinA-2)

=sin²A+2sinA+4

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