Question

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Answer 1

Answer:

given ,CDE congruence DCB

by cpct BC = DE , <CBD =DEC

In ∆ DGE and ∆ CGB

<CGB=<DGE (vertically opposite angle )

<CBG =<DEG ( :. CBD = DEC )

BC=DE ( by cpct )

by AAS DGE congruence CGB