helppppppppp!!! me for this 4
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11. It depends on the value of a,b&c whether they are negative or positive
12. x=y
=>x-y=0 is the required linear equation
13. x+2y=1
taking x=0 in this equation we get,
y=½
taking y=0 in this equation we get,
x=1
so the required solutions for this equation is
(0,½) , (1,0)
14. for c≠0 the given statement is true as ,
y=mx+c
if we put x=0 we will get,
y=c
that is for the value of y to be 0, c must be equal to zero that's the only way it will pass through origin otherwise not
12. x=y
=>x-y=0 is the required linear equation
13. x+2y=1
taking x=0 in this equation we get,
y=½
taking y=0 in this equation we get,
x=1
so the required solutions for this equation is
(0,½) , (1,0)
14. for c≠0 the given statement is true as ,
y=mx+c
if we put x=0 we will get,
y=c
that is for the value of y to be 0, c must be equal to zero that's the only way it will pass through origin otherwise not
snehabuddhdevpa5ygi:
can you explain 12
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