Physics, asked by badruddin24, 1 year ago

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Answered by prashanttyagi199931
1

Answer:

Here is ur answer

we have , u=80, v=60, t=5s

Therefore , a=?

we know that v=u+at

60=80+a×5

60-80=5a

-20=5a

=>a=-20/5

=>a=-4

Hope it helps u☺☺

Answered by DevyaniKhushi
0

{\boxed{\boxed{u = 80 \: {kmh}^{ - 1}   \:  \:  =  >  \:  \:  \frac{400}{18} \: {ms}^{ - 1}}}} \\  \\ {\boxed{\boxed{v = 60 \:  {kmh}^{ - 1}   \:  \: =  > \:  \:   \frac{300}{18}  \:  {ms}^{ - 1}}}}  \\  \\{\boxed{\boxed{ t = 5 \: sec}}}

Now,

a =  \frac{v - u}{t}  \\  \\   \:  \:  \: =  \frac{ \frac{300}{18} -  \frac{400}{18}  }{5}  \\  \\  \:  \:  \:  =  \frac{ \frac{ - 100}{18} }{5}  \\  \\  \:  \:  \:   =  \frac{ - 100}{18 \times 5}  \\  \\  \:  \:  \:  =  \frac{ - 20}{18}  \: \:   {ms}^{ - 2}

Hence,

{\boxed{\red{\boxed{ \large{Acceleration \:  \: of \:  \: bus \:  \: is \:  \:  \frac{ - 20}{18}  \:  \:  {ms}^{ - 2} }}}}}

{ \Huge{Or,}}

{\boxed{\boxed{u = 80 \: {kmh}^{ - 1}   \:  \:  =  >  \:  \:  22.2 \: {ms}^{ - 1} }}\\  \\{\boxed{\boxed{ v = 60 \:  {kmh}^{ - 1}   \:  \: =  > \:  \:   16.6  \:  {ms}^{ - 1}}} } \\  \\ {\boxed{\boxed{t = 5 \: sec}}}}

Now,

a =  \frac{v - u}{t}  \\  \\   \:  \:  \: =  \frac{16.6 - 22.2}{5}  \\  \\  \:  \:  \:  =  \frac{ - 5.6}{5}  \\  \\  \:  \:  \:  =  - 1.12 \:  \: {ms}^{ - 2}

Hence,

{\boxed{\red{\boxed{ \Large{Acceleration \:  \: of \:  \: bus \:  \: is \:  \: - 1.12  \:  \: {ms}^{ - 2} }}}}}

<marquee>MARK BRAINLIEST

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