Question

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10. Consider the arithmetic sequence 184, 178,
172, 166, ............
a) Write down the algebraic form (nth term)
of the sequence.
11
tii​

Answer 1

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Answer 2

The algebric form of the sequence 184, 178, 172, 166, .... is 190-6n

Step-by-step explanation:

The given AP is

$184, 178, 172, 166, ....$

Here first term of the AP

$a=184$

Common difference of the AP

$d=178-184=-6$

We know that the nth term of an AP whose first term is $a$ and common difference is $d$ is given by

$\boxed{a_n=a+(n-1)d}$

Therefore,

The nth term of the given AP

$a_n=184+(n-1)(-6)$

$\implies a_n=184-6n+6$

$\implies \boxed{a_n=190-6n}$

Hope this answer is helpful.

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