Hemant is twice as old as Arif. Five years ago his age was three times Arif’s age. Find their present ages.
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Answer:
Let the present ages of arjun and shriya be x and y respectively.
Let the present ages of arjun and shriya be x and y respectively.x = 2y
Let the present ages of arjun and shriya be x and y respectively.x = 2yThen , 5 yrs ago , their ages will be x-5 and y - 5 yrs old respectively. Acc. To Ques :-
Let the present ages of arjun and shriya be x and y respectively.x = 2yThen , 5 yrs ago , their ages will be x-5 and y - 5 yrs old respectively. Acc. To Ques :-x - 5 = 3 (y - 5)
Let the present ages of arjun and shriya be x and y respectively.x = 2yThen , 5 yrs ago , their ages will be x-5 and y - 5 yrs old respectively. Acc. To Ques :-x - 5 = 3 (y - 5)x - 5 = 3 y - 15
Let the present ages of arjun and shriya be x and y respectively.x = 2yThen , 5 yrs ago , their ages will be x-5 and y - 5 yrs old respectively. Acc. To Ques :-x - 5 = 3 (y - 5)x - 5 = 3 y - 15x = 3y - 10
Let the present ages of arjun and shriya be x and y respectively.x = 2yThen , 5 yrs ago , their ages will be x-5 and y - 5 yrs old respectively. Acc. To Ques :-x - 5 = 3 (y - 5)x - 5 = 3 y - 15x = 3y - 10Substituting x’ value
Let the present ages of arjun and shriya be x and y respectively.x = 2yThen , 5 yrs ago , their ages will be x-5 and y - 5 yrs old respectively. Acc. To Ques :-x - 5 = 3 (y - 5)x - 5 = 3 y - 15x = 3y - 10Substituting x’ value2y = 3y - 10
Let the present ages of arjun and shriya be x and y respectively.x = 2yThen , 5 yrs ago , their ages will be x-5 and y - 5 yrs old respectively. Acc. To Ques :-x - 5 = 3 (y - 5)x - 5 = 3 y - 15x = 3y - 10Substituting x’ value2y = 3y - 10y = 10 and x = 2y = 2 × 10 = 20 .
Let the present ages of arjun and shriya be x and y respectively.x = 2yThen , 5 yrs ago , their ages will be x-5 and y - 5 yrs old respectively. Acc. To Ques :-x - 5 = 3 (y - 5)x - 5 = 3 y - 15x = 3y - 10Substituting x’ value2y = 3y - 10y = 10 and x = 2y = 2 × 10 = 20 .Arjun ‘s age = 20 and Shriya ‘s age = 10.