Math, asked by arshitaics8, 19 days ago

Hemispherical bowl is made of steel 0.25 CM thick. If the inner radius of the bowl is 3.25 CM then the outer curved surface area of the bowl is

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Answers

Answered by kunaldutt04012007
2

Step-by-step explanation:

inner radius=3.25 cm

thickness=0.25 cm

outer radius= 3.25+0.25=3.50 cm

CSA OF HEMISPHERE = 2×22/7×3.50×3.50=77 cm

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