Question

Hemispherical bowl of internal and external diameter 8 cm and 12 cm are melted to form a right circular cylinder of radius 7 cm find the height of the cylinder

Answer 1

Answer:

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If any solid particle is melted and formed new particle by it then

volume of first particle=volume of 2nd particle

now,

volume of bowl=2/3π{R^3-r^3}

where R is external and r is internal radius of bowl

volume of bowl =2/3 π{(5)^3-(3)^3}

=2/3 x πx{125-27}

=2/3 x π x 98

=196/3π cm^3

let length of cylinder =h

volume of cylinder=πR1^2.h

=π(7)^2.h

now,

49π.h=196π/3

h=4/3 cm

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Answer 2

Step-by-step explanation:

volume of bowl=2/3π{R^3-r^3}

volume of bowl =2/3 π{(5)^3-(3)^3}

=2/3 x πx{125-27}

=2/3 x π x 98

=196/3π cm^3

let length of cylinder =h

volume of cylinder=πR1^2.h

=π(7)^2.h

now,

49π.h=196π/3

h=4/3 cm