Question

hemoglobin contains 0.33% iron by mass. the molucler mass of hemoglobin is approximately 67200.the number of iron atom(AT mass of fe=56) present in one molucle of hemoglobin are:-
(1)6
(2)1
(3)4
(4)2​

Answer 1

Answer:

(3) 4

Explanation

100g haemoglobin = 0.33 g Iron.

100g haemoglobin = 0.33 g Iron.67200g = 67200 x 0.33/ 100 = 224.44 g iron.

100g haemoglobin = 0.33 g Iron.67200g = 67200 x 0.33/ 100 = 224.44 g iron.Now, 56g iron = 6.022x10^23 atoms.

100g haemoglobin = 0.33 g Iron.67200g = 67200 x 0.33/ 100 = 224.44 g iron.Now, 56g iron = 6.022x10^23 atoms.So 224.44g = 224.44x 6.022x10^23/ 56 = 24.13x10^23 atoms.

100g haemoglobin = 0.33 g Iron.67200g = 67200 x 0.33/ 100 = 224.44 g iron.Now, 56g iron = 6.022x10^23 atoms.So 224.44g = 224.44x 6.022x10^23/ 56 = 24.13x10^23 atoms.Since 6.022x10^23 molecules of haemoglobin = 24.13x10^23 atoms of iron,

100g haemoglobin = 0.33 g Iron.67200g = 67200 x 0.33/ 100 = 224.44 g iron.Now, 56g iron = 6.022x10^23 atoms.So 224.44g = 224.44x 6.022x10^23/ 56 = 24.13x10^23 atoms.Since 6.022x10^23 molecules of haemoglobin = 24.13x10^23 atoms of iron,1 molecule of haemoglobin = 24.13x10^23/6.022x10^23 = 4 atoms of Fe.

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