Question

Hemoglobin contains 0.33% of Iron by weight. If 1 molecule of Hemoglobin contains two iron atoms, the molecular weight of Hemoglobin will be (at. Wt. of F=56 ) nearly​

Answer 1

Answer:

Percentage of Fe=0.33 % molecular weight of haemoglobin

Percentage of Fe=0.33 % molecular weight of haemoglobinWeight of Fe present = 1000.33×67200 = 221.8

Percentage of Fe=0.33 % molecular weight of haemoglobinWeight of Fe present = 1000.33×67200 = 221.8One Fe weighs 55.8 g

Percentage of Fe=0.33 % molecular weight of haemoglobinWeight of Fe present = 1000.33×67200 = 221.8One Fe weighs 55.8 gTherefore, 55.8221.8 =4

Explanation:

hope it will help you

please mark it as brianlist