Question

hen a train is traveling along a straight track at 2 m/s, it egins to accelerate at a = etermine its velocity v after 7 seconds (60 v) m/s, where v is in m/s.​

Answer 1

Answer:

the first equation of motion

v = u+at

after putting values in the equation

60 = 2+(a)7

a = 58/7

a = 8ms^-2

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Answer 2

Answer:

8.285 m/s²

Explanation:

Given :

• Initial velocity of the train = u = 2 m/s

• Time taken by the train = t = 7 seconds

• Final velocity of the train = v = 60 m/s

To find :

• Acceleration of the train

Using the first equation of motion which says :

V=u+at

60=2+a(7)

60 = 2+7a

60-2 = 7a

58 = 7a

a = 58/7

a = 8.285 m/s²

The acceleration of the train in the above question is equal to 8.285 m/s²