Question

Hence
8
2. Find the remainder when xy - ax2 + 6x -a is divided by x - a.
Solution. Let p(x) = x3 - ax2 + 6x
ax² - a​

Answer 1

Answer:

ay+a

explanation:

let p(x) be xy-ax2+6x-a

x-a=0; x=a

so p(a)= (a)y-a(a)2+6(a)-a

ay-4a+6a-a

ay+6a-5a

ay+a is the answer

Answer 2

Answer:

x - a = 0

.°. x = a

$p(x) = {x}^{3} - a {x}^{2} + 6x - a \\ p(a) = {(a)}^{3} - a( {a}^{2} ) + 6(a) - a \\ = {a}^{3} - {a}^{3} + 6a - a \\ = 5a$

Thus the remainder is 5a