Question

Hence,
a profit of 20%!
16. Two goats were bought at the same cost. One was sold at a profit of 8% and the other was
at a loss of 10%. What is the cost price of each goat
, if the actual difference of the selling
were 1802
wed a profit of 7% and on
Calcu
The fo​

Answer 1

Correct Question:-

Two goats were bought at the same cost.One was sold at the profit of 8% and the other was sold at the loss of 10%. What is the cost price of each goat, if the actual difference of the selling prices were rupees 180.

Answer:-

Let the CP of each goat be Rs. x.

Given:

Profit on first goat = 8%

loss on second goat = 10%

We know that,

CP × (100 + profit%) / 100 = SP

So,

★ SP of first goat = x * (100 + 8) / 100

⟹ SP of first goat = 108x/100

Also,

CP × (100 - loss%) / 100 = SP

So,

⟹ SP of second goat = x * (100 - 10) / 100

⟹ SP of second goat = 90x/100

Again,

Difference between their SP's = Rs. 180

So,

⟹ 108x/100 - 90x/100 = 180

⟹ (108x - 90x) / 100 = 180

⟹ 18x = 180 × 100

⟹ x = 18000/18

⟹ x = Rs. 1000

∴ The CP of each goat is Rs. 1000.

Answer 2

Appropriαte Question :

Two goats were bought at the same cost.One was sold at the profit of 8% and the other was sold at the loss of 10%. What is the cost price of each goat, if the actual difference of the selling prices were rupees 180.

Required Solution :

Given that,

• Profit on first goat = 8%
• loss on second goat = 10%

we have to find the cost price of each goat, if the actual difference of selling prices were ₹180.

___________

To do so,

• let's assume that Cost price is ₹ x.
• we need find the Selling price (S.P.) first.

$\large{\boxed{\sf{\red{ S.P. = C.P. \times \dfrac{100+profit \%}{100}}}}}$

Therefore, SP of the first goat will be

$\implies{\sf{ x \times \dfrac{100+8}{100}}}$

$\implies{\sf{ x \times \dfrac{108}{100}}}$

Also,

$\large{\boxed{\sf{\red{ S.P. = C.P. \times \dfrac{100-loss \%}{100}}}}}$

Therefore, SP of the second goat will be

$\implies{\sf{ x \times \dfrac{100-10}{100}}}$

$\implies{\sf{ \dfrac{90x}{100}}}$

Again, the difference between Selling prices is 180.

$\implies{\sf{ \dfrac{90x}{100} - \dfrac{180}{100} = 108}}$

$\implies{\sf{ \dfrac{108x-90x}{100} = 108}}$

$\implies{\sf{ \dfrac{18x}{100} = 180}}$

$\implies{\sf{ 18x= 180\times100}}$

$\implies{\sf{ 18x= 18000}}$

$\implies{\sf{ x= \dfrac{18000}{18}}}$

$\large\implies{\boxed{\sf{\orange{1000}}}}$

∴ The CP of each goat is Rs. 1000.

And we are done! :D

__________________________