Question

Hence, C can empty the full talk III 100 MILLJ.
6. Two pipes can fill a cistern in 14 hours and 16 hours respectively. The
pipes are opened simultaneously and it is found that due to leakage in
the bottom it took 32 minutes more to fill the cistern. When the cistern
is full, in what time will the leak empty it?
1
15​

Answer 1

Answer:

Efficiency of pipe A = 1/14

Efficiency of pipe B = 1/16

Efficiency of leakage C = - 1/n

Combined efficiency of pipe A and B = 1/14 + 1/16 = 15/112

The two pipes can fill the cistern in 112/15 hrs

When the leakage is allowed the time to fill the cistern = 112/15 + 32/60 = 480/60 = 8 hrs

Therefore

1/14 + 1/16 - 1/n = 1/8

1/n = 15/112 - 1/8 = 1/112

The leakage can empty the cistern in 112 hrs

Step-by-step explanation:

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