Question

Hence proved.
6. Prove that, of all the parallelograms of given
sides, parallelogram which is a rectangle has the
greatest area.
Col.​

Answer 1

Answer:

where is the parallelogram??????

Step-by-step explanation:

ABCD is a rectangle and ABFE is a parallelogram, such that

AD = BC = AE = BF

Area of rectangle = base x altitude

= AB x AD

Area of parallelogram ABFC = base x altitude

= AB x EG

In AGE, AE > EG (AE is the hypotenuse of right triangle)

But AD = AE

AD > EG

Hence, ar(rectangle ABCD) > ar (parallelogram ABFE)