Question

Hence, ZP = 36°, ZQ =
Example 2 :
In the given figure, the bisectors of ZB and ZD of a quadrilateral ABCD, meet CD and AB produced at P
1
and Q respectively. Prove that ZP + ZQ = -(ZABC + ZADC).
B
A
3
2
Р.
D
ni
01147623456​

Answer 1

Answer:

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