Question

Henrietta receives a Valentine’s card from a secret admirer. The admirer uses the codename ‘Dgplcokp’. Henrietta cracks the code and replies using the name ‘Jgptkgvvc’. What is her admirer’s name?

Answer 1

this type of questions are based on alphabetical order and sequences.

Let's try to solve the question,
the admirer use the code name 'Dgplcokp'
and Henrietta using the code 'Jgptkgvvc'
you can observed that ,
Total number of alphabets used by Henrietta is 9 and number of alphabets used in Henrietta 's name is also 9.

hence, we can say that ,
'jgptkgvvc' code used for Henrietta's name ,

now, be clear here,
H, i, j <=> H = j
e , f , g <=> e =g
n, o, p <=> n = p
r, s, t <=> r = t
i , j, k <=> i = k
e , f , g <=> e = g
t , u , v <=> t = v
t, u, v <=> t = v
a ,b , c <=> a = c

now, you understand ,
the code is 'jgptkgvvc' are All alphabets of her name ' Henrietta' are related alphabetical sequence.

so now, code 'Dgplockp'
b, c , d <=> d = b
e , f , g <=> g = e
n, o, p <=> p = n
j, k , l <=> l = j
a , b, c <=> c = a
m, n , o <=> o = m
I,j, k <=> k = i
n, o, p <=> p = n

hence, code 'Dgplcokp' is 'Benjamin'

hence, her admirer's name ' Benjamin'

Answer 2

Answer:micheal I guess

Step-by-step explanation:I don’t know