Question

Henry law constant for solubility of methane in benzene is 4.7 × 10^ - 5 hg mol dm^-1 at constant temperature calculate solubility of methane at 760 mm hg pressure at same temperature​

Answer 1

As we know that

p = k x c

We have given p = 760 mm, k = 4.27x 10^(-5)

Putting the given values in equation

760 = 4.27x 10^(-5)x c

Or

c = 760 / 4.27x 10^(-5)

c = 178 x 10^(5)