Henry law constant of CO2 in water at 298K is 5/3k bar. If pressure of CO2 is 0.01bar, find it's mole fraction?
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Answered by
14
Answer:6x10^-6
Explanation: we know, p = KH x X
Here, Partial pressure of CO2 is given 0.01 bar
And KH is given, 5/3 K bar
So, we have to find Xco2 :
A/t formula:
p = KH x Xco2
0.01 = 5/3x1000 x Xco2
Solving this we get, Xco2 = 6x10^-6
Hope this helps :)
Answered by
0
Answer:
mol-1 and C = 2*10-5 M into the Henry's law formula: P = kH*C = (1.6*103 atm. L. mol-1) * (2*10-5 mol.
Explanation:
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