Question

Henry's constant values of H2 & CH4 in water are observed to be 71.18 k.bar and 41.85 k.bar respectively. Which is relatively more soluble in water?​
Please answer properly

Answer 1

Answer:

He<N2<H2<O2

K H = P/X

At constant pressure, K

H

is inversely proportional to x. Therefore, the higher the K

H

lower the solubility.

The increasing solubility order is:

He<N

2

<H

2

<O

2