Question

Henry's law constant for CO2 in water is 1.67×108 Pa at 298K. Calculate the quantity of CO2 in 500mL of soda water when packed under 2.5 atm CO2 pressure at 298K.

Answer 1

It is given that:

KH= 1.67 × 108Pa

PCO2 = 2.5 atm = 2.5 × 1.01325 × 105Pa

= 2.533125 × 105Pa



According to Henry's law:

PCO2 = KHX

⇒ x = PCO2 / KH

= 2.533125 × 105 / 1.67 × 108

= 0.00152



We can write,

[Since, is negligible as compared to]



In 500 mL of soda water, the volume of water = 500 mL

[Neglecting the amount of soda present]

We can write:

500 mL of water = 500 g of water

=500 / 18 mole of water

= 27.78 mol of water

Now, nCO2 / nH2O = x

nCO2 / 27.78 = 0.00152

nCO2 = 0.042 mol

Hence, quantity of CO2 in 500 mL of soda water = (0.042 × 44)g

= 1.848 g

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