Question

Henry’s law constant for the molality of methane in benzene at 298 K is 4.27*105 mm Hg.Calculate the solubility of methane in benzene at 298 k under 760 mm Hg.

Answer 1

Question

Henry’s law constant for the molality of methane in benzene at 298 K is 4.27*105 mm Hg .Calculate the solubility of methane in benzene at 298 k under 760 mm Hg.

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Solution:

Given that Henry’s law constant

⇒kH = 4.27 × 105 mm Hg

⇒p = 760 mm Hg

If X is the molar fraction then

According to Henry’s law,

⇒p = kH X

⇒760  = 4.27 × 105 × X    

Divide by 4.27 × 105  ,we get

⇒Molar fraction, X

⇒ $\frac{760}{4.27 *10^{5} }$

⇒  $178 *10^{-5}$

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