Question

Heo brainly members


The diameter of the base of a right circular cylinder is 42 cm and it's height is 10 cm. Find the area of the curved surface and total surface area. ​

Answer 1

Hello dear❤️

Solution :

Diameter of the base of the cylinder = 42 cm

Radious of the base of the cylinder = 21 cm

Height of the base of the cylinder =10cm

Curved surface area of the cylinder

$2 \: \pi \: r \: h$

$2 \times \frac{22}{7} \times 21 \times 10 \: {cm}^{2}$

$2 \times 22 \times 3 \ \times 10 {cm}^{2}$

$1320 \: {cm}^{2}$

Total surface area of the cylinder

$2 \: \pi \: r (h + r)$

$2 \times \frac{22}{7} \times 21(10 + 21) \: {cm}^{2}$

$2 \times 22 \times 3 \times 31 \: {cm}^{2}$

$4092 \: {cm}^{2}$

Hope this helps

@adiba31❤️☺️

Answer 2

$\huge{\boxed{\boxed{Hi Dear!!!}}}$

$\huge{\mathfrak\red{Here \:is \:your \:answer}}$

$\huge{\mathcal\pink{Question}}$

The diameter of the base of a right circular cylinder is 42 cm and it's height is 10 cm. Find the area of the curved surface and total surface area.

$\huge{\mathcal\pink{Solution-}}$

Diameter of the base of the cylinder= 42cm

Radius of the base of the cylinder= 21cm

Height of the base of the cylinder= 10cm

$\underline\red{Curved \:surface \:area \:of \:cylinder}$

2 π r h

2 × $\frac{2}{7}$ × 21 × 10cm²

2 × 22 × 3 × 10cm²

1320cm²

$\underline\red{Total \:surface \:area \:of \:cylinder}$

2 π r (h + r)

2 × $\frac{22}{7}$ × 21 (10 + 21)cm²

2 × 22 × 3 × 31cm²

4092cm²

$\huge{\mathfrak\red{Hope \:it \:is \:hepful}}$

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