Question

heptane and octane form an ideal solution of 23g of heptane 31g of octane calculate mole fraction of each

Answer 1

Answer:Mole fraction of heptane is 0.4582 and mole fraction of octane is 0.5418.

Explanation:

Moles of heptane in solution =$n_1=\frac{23 g}{100.21 g/mol}=0.2295 mol$

Moles of octane in solution =$n_2=\frac{31 g}{114.23 g/mol}=0.2713 mol$

Mole fraction of heptane:

$\chi_1=\frac{n_1}{n_1+n_2}=\frac{0.2295 mol}{0.2295 mol+0.2713 mol}=0.4582$

Mole fraction of octane:

$\chi_2=\frac{n_2}{n_1+n_2}=\frac{0.2713 mol}{0.2295 mol+0.2713 mol}=0.5418$