Question

Here 27 to the power n
Please answer

Answer 1

$m - n = 1 \\ suppose \: m = 1 \\ 1 - n = 1 \\ - n = 0 \\ n = 0 \\ now \: we \: have \: m = 1 \: and \: n = 0 \\ \frac{ {9}^{n} \times {3}^{2} \times {3}^{n} - {27}^{n} }{ {3}^{3m} \times {2}^{3} } = \frac{1}{27} \\ \frac{ {9}^{0} \times 9 \times {3}^{0} - {27}^{0} }{ {3}^{3 \times 1} \times 8} = \frac{1}{27} \\ \frac{1 \times 9 \times 1 - 1}{27 \times 8} = \frac{1}{27} \\ \frac{9 - 1}{27 \times 8} = \frac{1}{27} \\ \frac{8}{27 \times 8} = \frac{1}{27} \\ \frac{1}{27} = \frac{1}{27}$