Question

Here am came back with an some interesting Questions in physics .Plz help me . . .

A body is projected along a rough inclined plane of coefficient of Kinetic friction uk with an initial velocity "u" . It travels distance "l" up the plane and retraces its path and reaches and same point projection with velocity 'v'

Answer should be in terms of u/v = √tan theta + uk / tantheta-uk​

Answer 1

Answer:

ta < t d

Explanation:

Let the velocity of projection be V and the velocity of the block when it returns back = V'. Then V > V' since some kinetic energy is lost to friction.

Hence, the average velocity during ascent is greater than the average velocity during descent. If the velocity is greater the time taken becomes lesser.

Answer 2

Answer:

Let the velocity of projection be V and the velocity of the block when it returns back = V ' . Then V > V ' since some kinetic energy is lost to friction . Hence , the average velocity during ascent is greater than the average velocity during descent . If the velocity is greater the time taken becomes lesser

hope it's help you drop some thanks