Question

Here are the first five terms of an arithmetic sequence. 26 19 12 5 -2 Find an expression, in terms of n, for the nth term of this sequence.

NO BAD ANSWERS ! OR I WILL REPORT YOU

Answer 1

ANSWER:

Given AP is,

26, 19, 12, 5, -2

Here,

a = 26

d = t2 - t1 = 19 -26 = -7

Now,

tn = a + ( n - 1 ) d

= 26 + ( n - 1 ) × ( -7 )

= 26 - 7n + 7

=> tn = 33 - 7n