Here are the first four terms of an arithmetic sequence.
6 10 14 18
Write down an expression, in terms of n , for the (n+1)th term of this sequence.
Answers
Answered by
10
Answer:
4(n-1) + 6
Step-by-step explanation:
So, as you can see, the sequence seems to be increasing by 4 each time.
So, start by finding n = 0.
6 - 4 = 2.
take 2 and add 4 * (n-1) since each time n increases you would add 4.
so the equation for the current term would be 2 + 4(n-1). In order to find the equation for the term after that just add 4 to the equation.
So the answer would be 4(n-1) + 6.
Answered by
0
Answer:
Step-by-step explanation:
Given,
Common Difference ( d ) = 4
First term ( a ) = 6
tₙ = (a + ( n - 1 )d)
( n + 1 )th term = (a + n d) -----------------(ii)
Substituting the value of n in equation (ii)
(n+1)th term = [a + { a + ( n- 1 )d} d ]
(n+1)th term = [ a + ad + nd² - d²]
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