Question

here are three galleries in a coal mine.On the first day two galleries are operative and after some time the third gallery is made operative.With this the output of the mine became half as large again.What is the capacity of the second gallery as a percentage of the first if it is given that a four-month output of the first and the third galleries was the same as the annual output of the second gallery? ​

Answer 1

Answer:

Let A,BC are the galleries.

Given

A+B=1

A+B+C=1.5

4(A+C)=12B

From 2nd and third equations

B=1.5/4

Substituting B in 1st eq we get

A=2.5/4

So capacity of B as percentage of A=1.5/2.5=60%

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