Question

here are three resistors joined in series in a system having resistance equal to 10 Ω, 20 Ω and 30 Ω respectively. If the potential difference of the circuit is 240 V, find the total resistance and current through the circuit. [5]

Answer 1

Answer:

4 ampere

Explanation:

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Answer 2

Given,

Three resistors joined in series in a system having a resistance equal to 10 Ω, 20 Ω, and 30 Ω respectively. The potential difference of the circuit is 240 V.

To find,

Total resistance and current through the circuit.

Solution,

• Three resistors 10 Ω, 20 Ω, and 30 Ω  are joined in series respectively.

• To calculate overall resistance we can simply add the resistance of all the three resistors as they are in series.

• Therefore, the overall resistance of the circuit is 10 Ω + 20 Ω + 30 Ω.= 60 Ω.

According to Ohm's law, Current passing through a conductor between two points is directly proportional to the voltage or potential difference across the two points.

V = IR

Potential difference(V) = 240 V.

Overall resistance(R) = 60 Ω.

Current flowing through the circuit(I) = 240V/60Ω.

I = 4 Amperes.

Hence, the total resistance is 60 Ω, and the current flowing through the circuit is 4 Amperes.