Math, asked by ri168, 4 months ago

Here are two problems. See carefully
i. Sabina is selling toffees at 3 for Rs 6/-. How much would 9 toffees cost?
ii. Naina is selling toffees at 3 for Rs 5/-. How much would 9 toffees cost?
Do you think that children would find these two problems equally difficult or is one easier than the other at 6th standard? Try explaining your answer carefully.

Answers

Answered by toibabhatt36
1

1.18Rs

2.15Rs

in first problem one toffee is equal to 2 Rs .so,9 toffee is equal to 9×2=18Rs

in second problem one toffee is equal to 1.66Rs . so,9 toffee is equal to 9×1.66=14.94 ( 15)

Answered by naikodiattri
1

No the answer will be non equal

Because the rupees are change

Step-by-step explanation:

Sabina sells toffees 3 for Rs 6/-

3 for 6 , 6 for 12 , 9 for 18.

For 9 toffees Rs 18 /-

Naina sells toffees 3 for Rs 5/-

3 for 5 , 6 for 10 , 9 for 15.

For 9 toffees Rs 15/-

And The Answer will be this

And I Hope this will be Helpful

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