Science, asked by hvgp, 1 year ago

Here,
given ,
For block 'A'
mass=10kg
velocity=100m/s
time=10second
For block 'B'
mass=15kg
time=5 second
velocity=?

block a and b conservation of momentum kar raha means pehle takraya phir wapas gaya means pichhe block a takrane ke baad velocity 100m/s toh block b kitne velocity se pichhe jaayega

pls pls help to solve this problem

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Answers

Answered by Anonymous

We know that
Change in velocity(dv)=F*dt/m
. =16*2/4
. =8 m/s
therefore change in velocity =8m/s

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hvgp: sir ne pata nahi kaha se ye question diya

hvgp: kabhi 11 ka dete hai

hvgp: mai 9 me

hvgp: aap mujhe btao ki ye answer kaise aaya

hvgp: aur class kya lena dena hai

Answered by adyaxox

M1= 10kg ; u1= 0 ; v1= 100m/s

M2=15kg ; u2= 0 ; v2=?

m1u1 + m2u2= m1v1+ m2v2

=> 10*0+ 15*0= 10*100+ 15*v2

=> 0=1000+15v2

=> -1000= 15v2

= 1000/15=v2

= 66.66m/s

hvgp: takraya

hvgp: phir dono takrane ke baad pichhe gaya

hvgp: toh block a velocity 100m/s tha

hvgp: toh block b ka velocity kya hoga

hvgp: sir mujhe ye bataya es question ka matlb

adyaxox: wahi toh find kari hai upar, law of conservation of momentum se

hvgp: ok

hvgp: Thank you adyaxox

hvgp: I understand your answer

hvgp: Thanks adyaxox

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