Math, asked by kalpana2006, 10 months ago

here 'I' MEANS PERPENDICULAR


Find the area of the field ABCDEFA, in which BP I AD,
CR I AD, FQ I AD, ES I AD and AP = 20 m, AQ = 35 m,
AR = 58 m, AS = 65 m, AD = 75 m, BP = 15 m, CR = 20 m, ES = 15 m and FQ = 10 m.





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Answers

Answered by amitnrw
6

1985 m² is area of figure

Step-by-step explanation:

Area of Figure

= Area of ΔAQF  + area of Trapezium FQSE + area of ΔSED + area of ΔAPB + area of Trapezium PBCR + area of ΔRCD

Area of ΔAQF   = (1/2) AQ * QF  = (1/2) * 35 * 10  = 175 m²

QS = AS - AQ = 65 - 35 = 30

area of Trapezium FQSE = (1/2)(FQ + SE)* QS = (1/2) (35 + 15)(30)  = 750 m²

SD = AD - AS = 75 - 65 = 10

area of ΔSED  = (1/2) * SE * SD  = (1/2) * 15 * 10  = 75 m²

area of ΔAPB = (1/2) * AP * PB = (1/2) * 20 * 15 = 150 m²

PR = AR - AP = 58 - 20 = 38

area of Trapezium PBCR  = (1/2) (PB + RC)* PR = (1/2) (15 + 20) * 38 = 665 m²

RD = AD - AR = 75 - 58 = 17

area of ΔRCD = (1/2) * RD * RC = (1/2) * 17 * 20 = 170 m²

175 + 750 + 75 + 150 + 665 + 170

= 1985 m²

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Answered by sourandhubhatta
0

Answer:

1985m2

Step-by-step explanation:

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