here 'I' MEANS PERPENDICULAR
Find the area of the field ABCDEFA, in which BP I AD,
CR I AD, FQ I AD, ES I AD and AP = 20 m, AQ = 35 m,
AR = 58 m, AS = 65 m, AD = 75 m, BP = 15 m, CR = 20 m, ES = 15 m and FQ = 10 m.
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Answers
1985 m² is area of figure
Step-by-step explanation:
Area of Figure
= Area of ΔAQF + area of Trapezium FQSE + area of ΔSED + area of ΔAPB + area of Trapezium PBCR + area of ΔRCD
Area of ΔAQF = (1/2) AQ * QF = (1/2) * 35 * 10 = 175 m²
QS = AS - AQ = 65 - 35 = 30
area of Trapezium FQSE = (1/2)(FQ + SE)* QS = (1/2) (35 + 15)(30) = 750 m²
SD = AD - AS = 75 - 65 = 10
area of ΔSED = (1/2) * SE * SD = (1/2) * 15 * 10 = 75 m²
area of ΔAPB = (1/2) * AP * PB = (1/2) * 20 * 15 = 150 m²
PR = AR - AP = 58 - 20 = 38
area of Trapezium PBCR = (1/2) (PB + RC)* PR = (1/2) (15 + 20) * 38 = 665 m²
RD = AD - AR = 75 - 58 = 17
area of ΔRCD = (1/2) * RD * RC = (1/2) * 17 * 20 = 170 m²
175 + 750 + 75 + 150 + 665 + 170
= 1985 m²
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Answer:
1985m2
Step-by-step explanation:
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