Question

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Answer 1

Step-by-step explanation:

Given: (x - 2y)³ + (2y - 3z)³ + (3z - x)³

Let a = x - 2y, b = 2y - 3z, c = 3z - x.

⇒ a + b + c = x - 2y + 2y - 3z + 3z - x

                  = 0

When a + b + c = 0, then a³ + b³ + c³ = 3abc

= 3(x - 2y)(2y - 3z)(3z - x).

Hope it helps!

Answer 2

Let a=x-2y, b=2y-3z, c=3z-x

Now a+b+c=0

So

a^3+b^3+c^3=3a*b*c

So,

The required result is

3(x-2y)(2y-3z)(3z-x)