Math, asked by ShrutiJha03, 11 months ago

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Answered by Anonymous
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Answered by ayushiverma59334
1

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Step-by-step explanation:Solving L. H. S-

=sec2A/cosec2A =1/cos2A/1/sin2A =sin2A/cos2A=tan2A solving R.H.S- =(1-tanA/1-cotA)^2=(1)2+(tan)2-2tanA/(1)2+(cotA)2-2cotA=1+tan2A-2tanA/1+cot2A-2cotA=sec2A-2tanA/cosec2A-2cotA=

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