Question

Here Is A Question For You My Friends...!!☺️♥️️❣️
First Answer Will Be Brainliest❣️❣️

Answer 1

Hey

___________

Here is the answer.
Hope it helps :)

Answer 2

Answer:

tan²A

Step-by-step explanation:

(i)

$Given:\frac{1+tan^2A}{1+cot^2A}$

$=\frac{sec^2A}{cosec^2A}$

$=\frac{1}{cos^2A}*\frac{sin^2A}{1}$

$=\frac{sin^2A}{cos^2A}$

$=\boxed{tan^2A}$

(ii)

$Given: (\frac{1-tanA}{1-cotA})^2$

$=(\frac{1-tanA}{1-\frac{1}{tanA}})^2$

$=(\frac{1-tanA}{\frac{tanA-1}{tanA}})^2$

$=-(\frac{1-tanA}{\frac{1-tanA}{tanA}})^2$

$=(-tanA)^2$

$=\boxed{tan^2A}$

∴ (i) & (ii) = tan²A.

Hope it helps!