Question

HERE IS A RECTANGLE ABCD 20CM=WIDTH AND 30CM=LENGTH AND LETTERS ABCD THE LENGH OF THE RECTANGLE IS INCREASED BY 10% AND THE WIDTH OF THE RECTANGLE I INCREASED BY 5%. WHAT IS THE PERCENTAGE INCREASE THE PERIMETER OF THE RECTANGLE?

Answer 1

let T:R^2→R^2 be a linear transformation such that T(1,2)=(2,3),T(0,1)=(1,4). Then T(5,6)

Answer 2

Answer:

8%

Step-by-step explanation:

perimeter of the rectangle is 100cm to start off with.

find out:

the length=30cm

increase 30 cm by 10%=33cm

the width=20cm

increase 20cm by 5%=21cm

33+33+21+21

perimeter of the rectangle now is 108cm

so it's increased by 8

therefore it's increased by 8%