Question

HERE IS A RECTANGLE ABCD 30CM=WIDTH AND 20CM=LENGTH AND LETTERS ABCD THE LENGH OF THE RECTANGLE IS INCREASED BY 10% AND THE WIDTH OF THE RECTANGLE I INCREASED BY 5%. WHAT IS THE PERCENTAGE INCREASE THE PERIMETER OF THE RECTANGLE?

Answer 1

Answer:

width=30cm

length=20cm

length is increased by 10% i.e

20×10%=2

breadth is increased by 5%i.e

30×5%= 1.5

so perimeter equals 2 (l+b)

so 2×(2+1.5)

=7

Answer 2

The perimeter of the rectangle is increased by 7%.

Step-by-step explanation:

Consider the provided information.

The length of the rectangle ABCD is 20 cm.

The width of the rectangle ABCD is 30 cm.

First find the perimeter of ABCD:

Perimeter of rectangle is: $P=2(l+w)$

$P=2(20+30)$

$P=2(50)$

$P=100$

Hence, the perimeter of ABCD was 100 cm.

The length of the rectangle is increased by 10%.

10% of 20 is:

$20\times\frac{10}{100} =2$

That means the length of rectangle is increased by 2 cm.

New length of the rectangle is: 20+2=22 cm

The width of the rectangle is increased by 5%.

5% of 30 is:

$30\times\frac{5}{100} =1.5$

That means the width of rectangle is increased by 1.5 cm.

New width of the rectangle is: 30+1.5=31.5 cm

Now find the perimeter of new rectangle.

$P=2(22+31.5)$

$P=107$

The perimeter of rectangle is increased by 7 cm (107cm-100=7cm).

$\frac{7}{100}\times100=7\%$

Hence, the perimeter of the rectangle is increased by 7%.

#Learn more

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