Question

Here is an interesting physics question pls give the correct answer. Careful it is Quite CONFUSING....

Please don't give strange answers

A boy standing on a stationary lift open from above throws a ball upwards with the maximum initial speed he can
I.e. 49m/s
If the lift starts moving upwards with a uniform speed of 5m/s,
And the boy throws the ball upwards, how long will it take for the ball to return to his hands???
(hint: You may get 2 answers for the same question, if you see from different view,
You might use concept of relative velocity) ###
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Answer 1

Answer:

ANSWER

a) S=ut−

2

1

ut

2

⇒S=0

2

gt

2

=ut

t=

g

2u

=

9.8

2×49

t=10s

b) LiftmovingwithUniformspeed = 5m/s

Ballisthroughingfrominsidethelift

Relativevelocityofball=49m/s

⇒Relativeacceleration=10

Thus, u

relative

= velocityofbell

t=

g

r

2u

r

=

9.8

2×49

⇒t=10s

solution

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