Question

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HERE IS ANOTHER QUESTION FOR YOU ???


The sum of squares of two consecutive natural number is 244 . Find the numbers.

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Answer 1

x^2 + (x+1)^2 = 244
2x^2 + 2x - 243
Factorise and find x .........

Answer 2

Let the two consecutive natural numbers be 2x and 2x + 2.

Given that sum of squares of two consecutive natural numbers is 244.

= > (2x)^2 + (2x + 2)^2= 244

= > 4x^2 + 4x^2 + 4 + 8x = 244

= > 8x^2 + 8x + 4 = 244

= > 8x^2 + 8x = 244 - 4

= > 8x^2 + 8x = 240

= > x^2 + x = 30

= > x^2 + x - 30 = 0

= > x^2 + 6x - 5x - 30 = 0

= > x(x + 6) - 5(x + 6) = 0

= > (x - 5)(x + 6) = 0

= > x = 5, -6.

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Therefore,

= > 1st number = 2(5)

= 10

= > 2nd number = 2(5) + 2

= 12

(or)

= > 1st number = 2(-6)

= -12.

= > 2nd number = 2(-6) + 2

= -10.

Hope this helps!