Question

here is hr question

Look at the giVen figure and find .

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Solution :

(a) Since x,y and z are exterior angles of ∆ABC :

90+ x = 180° (Linear property)

=】 x = 90°

z = 30° = 180° ( Linear property)

=】 z = 150°

In ∆ ABC,

Angle A + B + C = 180°

(Sum of the angles of a ∆ is 180°)

90° + 30° + Angle C = 180°

Angle C = 180° - 120° = 160°

Now, y + Angle C = 180° (Linear property)

So, y = 180°- 60° = 120°

Therefore, x+ y+z = 90°+120°+150° = 360°


(b) Since x,y, z,w are the exterior angles of the quadrilateral ABCD :

In Quadrilateral ABCD,

Angle A + B + C + D = 360°

(Sum of four angles of a quadrilateral is 360°)

Angle A + 60° + 80° + 120° = 360°

Angle A + 260° = 360°

Angle A = 360° - 260° = 100°

Now, w = 180° - Angle A = 180° - 100° = 80°

z = 180° - Angle B = 180° - 60° = 120°

y = 180° - Angle C = 180°- 80° = 100°

x = 180° - Angle D = 180° - 120° = 60°

Therefore, x+y+z+w = 60°+ 100°+ 120° + 80° = 360°


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