Question

Here is intresting ques.for u ..

six years before age of motherwas equal to square of her sons age. three years hence,her age will be thrice the age of sonthen.
FIND PRESENT AGES OF MOTHER AND SON............
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Answer 1

Answer:

Persent age of mother = x2+6⇒36+6=42

Son = x+6=6+6=12

Explanation:

Let age of son 6 years before be x

then mother's age = x2

then, persent age son =x+6

mothers age =x2+6

After 3 year,

son =x+6+3=x+9

mother =x2+6+3=x2+9

A.T.Q

x2+9=3(x+9)

x2+9=3x+27

x2−3x−18=0

x2−6x+3x−18=0

x(x−6)+3(x−6)=0

(x+3)(x−6)=0

x=6        (-3 will neglect)

Persent age of mother = x2+6⇒36+6=42

Son = x+6=6+6=12