Question

here is the area of rectangle of 20 sq cm.draw a straight line in this rectangle and divide it into one rectangle and 2 equal triangle?​

Answer 1

Answer:

(a)

The given rectangle is divided into two equal triangles by drawing a line as shown below.

 Area of rectangle       = 20 square cm

 Area of each triangle = 12 of area of rectangle

                                    = (20 ÷ 2) square cm

                                    = 10 square cm

(b)

The given rectangle is divided into two equal rectangles by drawing a line as shown below.

 Area of rectangle = 20 square cm

 Thus, area of each small rectangle = 12 of area of rectangle

                                                         = (20 ÷ 2) square cm

                                                         = 10 square cm

(c)

The given rectangle is divided into one rectangle and two equal triangles by drawing 2 lines as shown below.

We will consider a square as complete if it is more than half-filled, and will ignore a square if it is less than half-filled.

Thus, in the red shaded region, we have 2 completely filled squares and 2 squares that are more than half-filled.

Thus, the area of red triangle = 4 square cm

Similarly, the area of green triangle = 4 square

• Thus, the area of rectangle = 12 square cm.

• Area of each of the triangle is 4 square cm.

Step-by-step explanation:

Sorry this is very big answer

Answer 2

Given the area of rectangle of 20 sq cm.

$\text { Here is a rectangle of an area of } 20 \text { square } \mathrm{cm} \text {. }$

$\text { Draw two straight lines in this rectangle to divide it into one rectangle and two equal triangles. }$The area of rectangle = 10 sq cm.

Area of each Triangle

= $\frac{1}{2}$ × Area of smaller rectangle

= $\frac{1}{2}$ × 10

= 5 Square cm

Hence the answer is 5 square cm.