Question

Here is the Question⚛⚛⚛⚛⚛⚛

places A and B are 100 km apart on a highway. one car starts from A and another from B at the same time . if the cars travel in the same direction at different speeds , they meet in 5 hours . if they travel towards each other , they meet in 1 hour .what are the speeds of the two cars?


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Answer 1

Let the speed of car at A be x km/h

and the speed of car at B be y km/h

According To The Question:

5x-5y = 100

=> x-y = 20.......(1)

and

x+y =100.........(2)

on solving equⁿ 1&2

x=60

&

y= 40

Answer 2

Hey

Buddy.....

Answer:

Let the speed of faster car = x km/h

Speed of slower car = y km/h

Relative speed when both car travels in same direction = x-y

If the cars travel in the same direction, they meet in 5 hours.

$speed \: = \frac{distance \:}{time}$

Total distance = 100 km

Total distance = 100 km

x-y = 100/5 ⇒ x-y = 20 …1

Relative speed when both car travels in different direction = x + y

If they travel towards each other, they meet in 1 hour.

x + y = 100 …2

Adding Eq. 1 and 2

x-y = 20

x + y = 100/2x = 120

$x = \frac{120}{2} = 60$

substituting x = 60 in eq. 2

60 + y = 100

y = 100-60

y = 40 km

Speed of the faster car = 60km/h

Speed of the slower car = 40km/h.

Hope this helps u dude