Question

Here is the question please answer fast.
Best answer i will mark as brainliest

Answer 1

Molecular mass of the compound = 67,000 amu

% of mass of iron in the compound = 0.333%

Mass percentage = (Mass of Iron/Mass of compound)*100 = 0.333

                              = Mass of iron = 0.333*67000/100

                                                      = 223.11 amu

   No of moles of Fe = 223.11/56

                                   =3.9 = 4 moles

1 mole = 6.022 * 10^24 molecules

4 moles = 24.088 * 10^24 molecules

No of iron atoms in one molecule = 24.088 * 10^24/6.022 * 10^24

                                                        = 4 atoms//